Different ways to find given number is Even or Odd in C

Once upon a day I faced this question in my college day ,"Write a program to find a number is Even or Odd". When I here it is , My mind said this so easy. But I know only a one way to find. So, after that I searched over my search engine for this question. And lastly I find many different and surprising ways..

Here I going to share my knowledge and opinions on finding a given is Even or Odd.

Method one:

Using modulus operator ( A basic way :))

Modulus operator returns the remainder in the division operation. Many people easily check the number is divisible by 2 and this same thing is happening in this method also.

#include <stdio.h>

int main(){

int n;
printf"Enter a number :");
scanf("%d",&n);
if(n%2==0)
printf("Given number is Even");
else
printf("Given number is Odd");

return 0;
}

Method Two:

Using Arithmetic operation ( A basic way :))

This technique looks so easy to understand and we do it in our elementary school levels.

#include <stdio.h>

int main(){

int n;
printf"Enter a number :");
scanf("%d",&n);
if(((n/2)*2)==n)
printf("Given number is Even");
else
printf("Given number is Odd");

return 0;
}

Using Bitwise & operator ( A basic way :))

Somebodies are feel hardness when hearing the words,"Bitwise","Bit manipulation"..

But these techniques are really not hard like they think! It is just a operations of a number system which has the base 2.

#include <stdio.h>

int main(){

int n;
printf"Enter a number :");
scanf("%d",&n);
if(n&1!=1)
printf("Given number is Even");
else
printf("Given number is Odd");

return 0;
}

Note in the binary system odd numbers are always has the 1 in their least significant bit (LSB) and the even is opposite to that.

Using Bitwise shift operators ( A basic way :))

#include <stdio.h>

int main(){

int n;
printf"Enter a number :");
scanf("%d",&n);
if((n>>1)<<1 == n)
printf("Given number is Even");
else
printf("Given number is Odd");

return 0;
}